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5x^2+17x-12=24-7x
We move all terms to the left:
5x^2+17x-12-(24-7x)=0
We add all the numbers together, and all the variables
5x^2+17x-(-7x+24)-12=0
We get rid of parentheses
5x^2+17x+7x-24-12=0
We add all the numbers together, and all the variables
5x^2+24x-36=0
a = 5; b = 24; c = -36;
Δ = b2-4ac
Δ = 242-4·5·(-36)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-36}{2*5}=\frac{-60}{10} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+36}{2*5}=\frac{12}{10} =1+1/5 $
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